Making a Java Makefile

Question

EDIT: Essentially, I am trying to do the same thing as typing \"javac sim.java\" and then \"java sim (commands)\". Is there a way to replace this using a makefile?

S

Answer 1

Using make with java can be an exercise in driving screws with a hammer as soon as you have more than one class.

Working java code will use packages. So you'll have a complex directory tree that mirrors your package structure, with your .java source files in it. Writing make rules that 'see' all those files is a pain.

You should invoke javac on all your source files at the same time to get correct results. So, the usual make pattern of 'run one command to turn one source file into one compiled file' does not work so well.

However, it seems as if your main problem at the moment is that you expect java to produce an executable; a file with a name like 'sim'. Nope, not going to happen in any simple way. The java compiler produces .class files; a whole tree of them for your source files. You can run directly from them, or you can package them up in a JAR file.

To get all the way to something that appears to be a simple command line executable, you need to use a more complex tool that wraps all this up with a script on the front.

For now, you just need to do:

java -cp . NAME_OF_THE_CLASS_IN_sim.java

to run after your makefile completes.