Passing file path as an argument in Java

Question

I have been working with buffering a file on my local drive to parse and obtain certain data. For test purposes I was easily able to do it this way:

public s         


        

Answer 1

You need to do this:

public static void main(String[] args) {
    String path = args[0];
    // ... 
    File CP_file = new File(path);
    // ... 
}