C++ literal integer type

Question

Do literal expressions have types too ?

long long int a = 2147483647+1 ;
long long int b = 2147483648+1 ; 
std::cout << a << \',\' << b ; /         


        

Answer 1

int a = INT_MAX ;
long long int b = a + 1 ; // adds 1 to a and convert it then to long long ing
long long int c = a; ++c; // convert a to long long int and increment the result with 1
cout << a << std::endl; // 2147483647
cout << b << std::endl; // -2147483648
cout << c << std::endl; // 2147483648
cout << 2147483647 + 1 << std::endl; // -2147483648 (by default integer literal is assumed to be int)
cout << 2147483647LL + 1 << std::endl; // 2147483648 (force the the integer literal to be interpreted as a long long int)

You can find more information about integer literals here.