PHP function missing argument error

Question

My validate function looks like that

function validate($data, $data2 = 0, $type)
{
...

Function call example

if ($result =          


        

Answer 1

You should at least set the $type in this line:

function validate($data, $data2 = 0, $type)

at NULL or '' as you can see here:

function validate($data, $data2 = 0, $type = null)

PHP let you to set a value for the parameters, but you can't define a parameter WITHOUT a preset value AFTER parameter(s) which HAVE a preset value. So if you need to always specify the third param, you have to switch the second and the third like this:

function validate($data, $type, $data2 = 0)