Explicit ignore warning from -Wcast-qual: cast discards ‘__attribute__((const))’ qualifier from pointer target type

Question

static char buf[8];
void foo(){
    const char* ptr = buf;
    /* ... */
    char* q = (char*)ptr;
}

The above snippet will generate \"warnin

Answer 1

Bit late, but you can also do this without mucking with warnings at all:

static char buf[8];
void foo(){
    const char* ptr = buf;
    /* ... */
    char* q = buf + (ptr-buf);
}

You end up with q = buf + ptr - buf = ptr + buf - buf = ptr, but with buf's constness.

(Yes, this allows you to remove const from any pointer at all; const is advisory, not a security mechanism.)