C code to count the number of '1' bits in an unsigned char

Question

I need C code to return the number of 1\'s in an unsigned char in C. I need an explanation as to why it works if it\'s not obvious. I\'ve found a lot of code for a 32-bit nu

Answer 1

As already answered, the standard ways of counting bits also work on unsigned chars.

Example:

    unsigned char value = 91;
int bitCount = 0;
while(value > 0)
{
    if ( value & 1 == 1 ) 
        bitCount++;
    value >>= 1;
}