How do you curry any javascript function of arbitrary arity?

Question

Let\'s say I have some function:

function g(a,b,c){ return a + b + c }

And I\'d like to turn it into its \"curried\" form (in quotations si

Answer 1

How about something like this:

function makeLazy(fn) {
    var len = fn.length;
    var args = [];
    return function lazy() {
        args.push.apply(args, arguments);
        if (args.length < len) {
            return lazy;
        } else {
            return fn.apply(this, args);
        }
    }
}

function f(a,b,c) { return a + b + c; }

var lazyF = makeLazy(f);
lazyF(1)(2)(3); // 6

var lazyF = makeLazy(f);
lazyF(1,2)(3); // 6

---

If you wanted a reusable function (I guess I can't tell exactly what you want), then this would work:

function makeCurry(fn) {
    return function curry() {
        var args = [].slice.call(arguments);
        return function() {
            return fn.apply(this, args.concat.apply(args, arguments));
        };
    }
}


function f(a,b,c) { return a + b + c; }

var curryF = makeCurry(f);
var addOneTwoAnd = curryF(1,2);

addOneTwoAnd(3); // 6
addOneTwoAnd(6); // 9