I have a file in the following format:
col1|col2|col3|col4 a|b|c|d e|f||h i|j|k|l
I would like to delete col3 (with the delimiter \"|\") fr
awk 'BEGIN{FS=OFS="|"}{print $1,$2,$4}' file
should give you the output.
it is the very basic awk usage.
edit
you didn't mention 70 columns... :(
try this:
awk -F'|' '{s="";for(i=1;i<=NF;i++){f=(NF==i)?"":FS;if(i!=3)s=s $i f;}print s}' file