How to wait until buffered channel (semaphore) is empty?

Question

I have a slice of integers, which are manipulated concurrently:

ints := []int{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

I\'m using a buffered channel

Answer 1

Use "worker pool" to process you data. It is cheeper than run goroutine for each int, allocate memory for variables inside it and so on...

ints := []int{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

ch := make(chan int)

var wg sync.WaitGroup

// run worker pool
for i := 2; i > 0; i-- {
    wg.Add(1)

    go func() {
        defer wg.Done()

        for id := range ch {
            // do something
            fmt.Println(id)
        }
    }()
}

// send ints to workers
for _, i := range ints {
    ch <- i
}

close(ch)

wg.Wait()