std::function -> function pointer

Question

Here is a code:

#include 
using namespace std::tr1;

typedef void(*fp)(void);

void foo(void)
{

}

void f(fp)
{

}

int main()
{
  functio         


        

Answer 1

You can't convert a std::function to a function pointer(you can do the opposite). You should use either function pointers, or std::functions. If you can use std::function instead of pointers, then you should.

This makes your code work:

typedef function fp;