Elegant Format for a MAC Address in Python 3.2

Question

I am looking for a more elegant solution to formatting a MAC address with colons. I am using Python 3.2. A fancy list comprehension perhaps?

s=\"\"
h=\"0023         


        

Answer 1

This is not the shortest solution, but it accepts all common types of mac formats as inputs. It also does some validation checks.

import re

def format_mac(mac: str) -> str:
    mac = re.sub('[.:-]', '', mac).lower()  # remove delimiters and convert to lower case
    mac = ''.join(mac.split())  # remove whitespaces
    assert len(mac) == 12  # length should be now exactly 12 (eg. 008041aefd7e)
    assert mac.isalnum()  # should only contain letters and numbers
    # convert mac in canonical form (eg. 00:80:41:ae:fd:7e)
    mac = ":".join(["%s" % (mac[i:i+2]) for i in range(0, 12, 2)])
    return mac

Here is a list of mac address strings and whether they will be considered as valid or invalid:

'008041aefd7e',  # valid
'00:80:41:ae:fd:7e',  # valid
'00:80:41:AE:FD:7E',  # valid
'00:80:41:aE:Fd:7E',  # valid
'00-80-41-ae-fd-7e',  # valid
'0080.41ae.fd7e',  # valid
'00 : 80 : 41 : ae : fd : 7e',  # valid
'  00:80:41:ae:fd:7e  ',  # valid
'00:80:41:ae:fd:7e\n\t',  # valid

'aa:00:80:41:ae:fd:7e',  # invalid
'0:80:41:ae:fd:7e',  # invalid
'ae:fd:7e',  # invalid
'$$:80:41:ae:fd:7e',  # invalid

All valid ones will be returned in the canonical form as:

'00:80:41:ae:fd:7e'