Specializing function template for reference types

Question

Why is the output of this code :

#include   
template void f(T param) 
{ 
   std::cout << \"General\" << std::e         


        

Answer 1

I know it is not answer but, IMHO you can try this, with a trait like approach in a struct:

template
struct value_traits
{
    static void print(){std::cout << "General" << std::endl ;} 
};

template<>
struct value_traits
{
    static void print(){std::cout << "const long" << std::endl ;} 
};

template<>
struct value_traits >
{
    static void print(){std::cout << "std::vector" << std::endl ; }
};

template<>
struct value_traits
{
       static void print(){std::cout << "const int" << std::endl ;} 
};