Conditionally passing arbitrary number of default named arguments to a function

Question

Is it possible to pass arbitrary number of named default arguments to a Python function conditionally ?

For eg. there\'s a function:

def func(arg, ar         


        

Answer 1

You can write a helper function

def caller(func, *args, **kwargs):
    return func(*args, **{k:v for k,v in kwargs.items() if v != caller.DONT_PASS})
caller.DONT_PASS = object()

Use this function to call another function and use caller.DONT_PASS to specify arguments that you don't want to pass.

caller(func, 'arg', 'arg2', arg3 = 'some value' if condition else caller.DONT_PASS)

Note that this caller() only support conditionally passing keyword arguments. To support positional arguments, you may need to use module inspect to inspect the function.