Conditionally passing arbitrary number of default named arguments to a function

Question

Is it possible to pass arbitrary number of named default arguments to a Python function conditionally ?

For eg. there\'s a function:

def func(arg, ar         


        

Answer 1

That wouldn't be valid Python syntax you have to have something after else. What is done normally is:

func('arg', 'arg2', 'some value' if condition else None)

and function definition is changed accordingly:

def func(arg, arg2='', arg3=None):
    arg3 = 'def' if arg3 is None else arg3