Conditionally passing arbitrary number of default named arguments to a function

Question

Is it possible to pass arbitrary number of named default arguments to a Python function conditionally ?

For eg. there\'s a function:

def func(arg, ar         


        

Answer 1

The only way I can think of would be

func("arg", "arg2", **({"arg3": "some value"} if condition == True else {}))

or

func("arg", "arg2", *(("some value",) if condition == True else ()))

but please don't do this. Use the code you provided yourself, or something like this:

if condition:
   arg3 = "some value",
else:
   arg3 = ()
func("arg", "arg2", *arg3)