Why is fwrite writing more than I tell it to?

Question

FILE *out=fopen64(\"text.txt\",\"w+\");
unsigned int write;
char *outbuf=new char[write];
//fill outbuf
printf(\"%i\\n\",ftello64(out));
fwrite(outbuf,sizeof(char),w         


        

Answer 1

The variable write is uninitialized and so the size of the array and the amount written will be essentially random.