How do you set the StartPosition of a Windows Forms form using code?

Question

Is there a way to set the StartPosition of a Windows Forms form using code? It seems whatever I try results in the StartPostion being the default.

Here is what I am

Answer 1

If I do a ShowDialog() and pass the parent it works ... but I really don't want to show it as a Dialog.

That is correct since ShowDialog would set frm.Parent == nvShowDeals.Parent
Since you are using .Show() then frm.Parent == null thus FormStartPosition.CenterParent is ignored.

So to accomplish this function I would make the following changes:

public DealsForm()
{
    InitializeComponent();
    //this.StartPosition = FormStartPosition.CenterParent;
}

//DealsForm_Load Event
private void DealsForm_Load(object sender, EventArgs e)
{
    this.Location = this.Owner.Location;  //NEW CODE
}

And Here I would make the following changes:

private void nvShowDeals_LinkClicked(object sender, LinkLabelLinkClickedEventArgs e)
{
    DealsForm frm = new DealsForm();

    frm.DataSource = this.Deals;
    frm.StartPosition = FormStartPosition.Manual; //NEW CODE
    frm.Show(this);
}