time.Millisecond * int confusion

Question

In the below example, if the 1000\'s are both int\'s (which I think they are) why would the bottom fail to compile?

//works
time.Sleep(1000 * time.Millisecon         


        

Answer 1

You can make i a constant instead of a variable, if you are primarily interested in naming the value:

package main

import (
    "time"
)

func main() {
    // works:
    time.Sleep(1000 * time.Millisecond)

    // works also:
    const i = 1000
    time.Sleep(i * time.Millisecond)
}

In-reply-to: https://stackoverflow.com/a/19338130/11630268