How do you parse the Subject Alternate Names from an X509Certificate2?

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孤街浪徒
孤街浪徒 2020-12-18 19:40

Is there an easy way to get the Subject Alternate Names from an X509Certificate2 object?

        foreach (X509Extension ext in certificate.Extensions)
               


        
8条回答
  •  一整个雨季
    2020-12-18 20:17

    All of the answers here are either platform or OS language specific or are able to retrieve only one alternative subject name so I wrote my own parser by reverse engineering raw data which can parse DNS and IP Addresses and suits my needs:

    private const string SAN_OID = "2.5.29.17";
    
    private static int ReadLength(ref Span span)
    {
        var length = (int)span[0];
        span = span[1..];
        if ((length & 0x80) > 0)
        {
            var lengthBytes = length & 0x7F;
            length = 0;
            for (var i = 0; i < lengthBytes; i++)
            {
                length = length * 0x100 + span[0];
                span = span[1..];
            }
        }
        return length;
    }
    
    public static IList ParseSubjectAlternativeNames(byte[] rawData)
    {
        var result = new List(); // cannot yield results when using Span yet
        if (rawData.Length < 1 || rawData[0] != '0')
        {
            throw new InvalidDataException("They told me it will start with zero :(");
        }
    
        var data = rawData.AsSpan(1);
        var length = ReadLength(ref data);
        if (length != data.Length)
        {
            throw new InvalidDataException("I don't know who I am anymore");
        }
    
        while (!data.IsEmpty)
        {
            var type = data[0];
            data = data[1..];
    
            var partLength = ReadLength(ref data);
            if (type == 135) // ip
            {
                result.Add(new IPAddress(data[0..partLength]).ToString());
            } else if (type == 160) // upn
            {
                // not sure how to parse the part before \f
                var index = data.IndexOf((byte)'\f') + 1;
                var upnData = data[index..];
                var upnLength = ReadLength(ref upnData);
                result.Add(Encoding.UTF8.GetString(upnData[0..upnLength]));
            } else // all other
            {
                result.Add(Encoding.UTF8.GetString(data[0..partLength]));
            }
            data = data[partLength..];
        }
        return result;
    }
    
    public static IEnumerable ParseSubjectAlternativeNames(X509Certificate2 cert)
    {
        return cert.Extensions
            .Cast()
            .Where(ext => ext.Oid.Value.Equals(SAN_OID))
            .SelectMany(x => ParseSubjectAlternativeNames(x.RawData));
    }
    

    I also found this test in corefx repo itself: https://github.com/dotnet/corefx/blob/master/src/System.Security.Cryptography.Encoding/tests/AsnEncodedData.cs#L38

    The idea there is to just split the asnData.Format result on ':', '=', ',' and take every other value which is a much easier approach:

    byte[] sanExtension =
    {
        0x30, 0x31, 0x82, 0x0B, 0x65, 0x78, 0x61, 0x6D,
        0x70, 0x6C, 0x65, 0x2E, 0x6F, 0x72, 0x67, 0x82,
        0x0F, 0x73, 0x75, 0x62, 0x2E, 0x65, 0x78, 0x61,
        0x6D, 0x70, 0x6C, 0x65, 0x2E, 0x6F, 0x72, 0x67,
        0x82, 0x11, 0x2A, 0x2E, 0x73, 0x75, 0x62, 0x2E,
        0x65, 0x78, 0x61, 0x6D, 0x70, 0x6C, 0x65, 0x2E,
        0x6F, 0x72, 0x67,
    };
    
    AsnEncodedData asnData = new AsnEncodedData(
        new Oid("2.5.29.17"),
        sanExtension);
    
    string s = asnData.Format(false);
    // Windows says: "DNS Name=example.org, DNS Name=sub.example.org, DNS Name=*.sub.example.org"
    // X-Plat (OpenSSL) says: "DNS:example.org, DNS:sub.example.org, DNS:*.sub.example.org".
    // This keeps the parsing generalized until we can get them to converge
    string[] parts = s.Split(new[] { ':', '=', ',' }, StringSplitOptions.RemoveEmptyEntries);
    // Parts is now { header, data, header, data, header, data }.
    string[] output = new string[parts.Length / 2];
    
    for (int i = 0; i < output.Length; i++)
    {
        output[i] = parts[2 * i + 1];
    }
    

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