Anonymous Namespace Ambiguity

Question

Consider the following snippet:

void Foo() // 1
{
}

namespace
{
  void Foo() // 2
  {
  }
}

int main()
{
  Foo(); // Ambiguous.
  ::Foo(); // Calls the Foo         


        

Answer 1

The only real way is to put the code you want to access that namespace within the namespace itself. There's no way to resolve to the unnamed namespace otherwise, since it has no identifier you can give it to solve the ambiguous resolution problem.

If your code is inside the namespace{} block itself, the local name gets priority over the global one, so a Foo() will call the Foo() within your namespace, and a ::Foo() will call the namespace at global scope.