Would you use num%2 or num&1 to check if a number is even?

Question

Well, there are at least two low-level ways of determining whether a given number is even or not:

 1. if (num%2 == 0) { /* even */ } 
 2. if ((num&1) ==          


        

Answer 1

They're both pretty intuitive.

I'd give a slight edge to num % 2 == 0, but I really don't have a preference. Certainly as far as performance goes, it's probably a micro-optimization, so I wouldn't worry about it.