Would you use num%2 or num&1 to check if a number is even?

Question

Well, there are at least two low-level ways of determining whether a given number is even or not:

 1. if (num%2 == 0) { /* even */ } 
 2. if ((num&1) ==          


        

Answer 1

Any modern compiler will optimise away the modulo operation, so speed is not a concern.

I'd say using modulo would make things easier to understand, but creating an is_even function that uses the x & 1 method gives you the best of both worlds.