Java 7 zip file system provider doesn't seem to accept spaces in URI

Question

I have been testing all possible variations and permutations, but I can\'t seem to construct a FileSystemProvider with the zip/jar scheme for a path (URI) that contains spac

Answer 1

Actually further analysis does seem to indicate there is a problem with the ZipFileSystemProvider. The uriToPath(URI uri) method contained within the class executes the following snippet:

String spec = uri.getSchemeSpecificPart();
int sep = spec.indexOf("!/");
if (sep != -1)
  spec = spec.substring(0, sep);
return Paths.get(new URI(spec)).toAbsolutePath();

From the JavaDocs of URI.getSchemeSpecificPart() we can see the following:

The string returned by this method is equal to that returned by the getRawSchemeSpecificPart method except that all sequences of escaped octets are decoded.

This same string is then passed back as an argument into the new URI() constructor. Since any escaped octets are de-escaped by getSchemeSpecificPart(), if the original URI contained any escape characters, they will not be propagated to the new URI - hence the exception.

A potential workaround - loop through all the available filesystem providers and get the reference to the one who's spec equals "jar". Then use that to create a new filesystem based on path only.