How do I deserialize JSON into a List with Kotlin + Jackson [duplicate]

Answer 1

The error you're getting is about following expression:

List::class.java

Because of how jvm treats generics there's no separate class for List thus compiler complains. Similarly in Java the following will not compile:

List.getClass()

Here's a sample that will deserialize the list properly:

val value:List = mapper.readValue(json, object : TypeReference>() {})

As @JaysonMinard has pointed out you can use jackson-module-kotlin to simplify the invocation to:

val genres: List = mapper.readValue(json)
// or
val genres = mapper.readValue>(json)

This is possible because of reified type parameters. Consider looking at Extensions to find out details.