argparse default option based on another option

Question

Suppose I have an argparse python script:

import argparse
parser = argparse.ArgumentParser()

parser.add_argument(\"--foo\", required=True)

Answer 1

Here's another attempt at writing a custom Action class

import argparse
class FooAction(argparse.Action):
    # adapted from documentation
    def __call__(self, parser, namespace, values, option_string=None):
        setattr(namespace, self.dest, values)
        defaultbar = getattr(namespace, 'bar')
        try:
            defaultbar = defaultbar%values
        except TypeError:
            # BAR has already been replaced
            pass
        setattr(namespace, 'bar', defaultbar)

parser = argparse.ArgumentParser()
parser.add_argument("--foo", required=True, action=FooAction)
parser.add_argument("--bar", default="%s_BAR")

args = parser.parse_args(['--foo', 'Foo', '--bar', 'Bar'])
# Namespace(bar='Bar', foo='Foo')
args = parser.parse_args(['--foo', 'Foo'])
# Namespace(bar='Foo_BAR', foo='Foo')
args = parser.parse_args(['--bar', 'Bar', '--foo', 'Foo'])
# Namespace(bar='Bar', foo='Foo')

Note that the class has to know the dest of the --bar argument. Also I use a '%s_BAR' to readily distinguish between a default value, and a non default one. This handles the case where --bar appears before --foo.

Things that complicate this approach are:

• default values are evaluated at add_argument time.
• default values are placed in the Namespace at the start of parse_args.
• flagged (optionals) arguments can occur in any order
• the Action class is not designed to handle interacting arguments.
• the bar action will not be called in the default case.
• the bar default could be a function, but something would have to check after parse_args whether it needs to be evaluated or not.

While this custom Action does the trick, I still think the addbar function in my other answer is a cleaner solution.