Suppose you are given an array of unsorted integers as
A = {3,4,5,1,4,2}
Input : 6
Output : {5,1}, {4,2}
If the numbers stored in the input array are only positive then I'd create another array K of k+1 ArrayList elements. Where k is the number you need them to add up to. Only two numbers less than k can add up to k (assuming we deal with positive ints} or in special case {0,k}. Then I would iterate through all elements of input array and for each int m that is less or equal to k I'd take its index and add that index to the array of ArrayList K at index m. Then I would iterate through first half of the array K and for each index i that has some ints stored in it I would find complementary index [k-i] and see if there are any values in it. If there are then those are your pairs. And btw this is O(n).
public static void findElemtsThatSumTo( int data[], int k){
List arrayK[]= new List[k+1];
for(int i=0; i();
for(int i=0; i