Swift sort dictionary by value

Question

I have a dictionary, [String : Double] with the following data:

Museum1 : 8785.8971799638
Museum2 : 34420.9643422388
Museum3 : 826.467789130732
         


        

Answer 1

Simple solution for Swift 4 and above...

let dict = ["Museum1":8785.8971799638,
            "Museum2":34420.9643422388,
            "Museum3":826.467789130732,
            "Museum4":304120.342151219]

let dictSortByValue = dict.sorted(by: {$0.value < $1.value} )

for item in dictSortByValue {
   print("\(item.key) \(item.value) ")
}

// Museum3 826.467789130732 
// Museum1 8785.8971799638 
// Museum2 34420.9643422388 
// Museum4 304120.342151219 

Apparently you can sort a Dictionary in Swift 4--no need to transform into an Array.