Swift sort dictionary by value

Question

I have a dictionary, [String : Double] with the following data:

Museum1 : 8785.8971799638
Museum2 : 34420.9643422388
Museum3 : 826.467789130732
         


        

Answer 1

In Swift 2.2, this works

for (k,v) in (Array(d).sort {$0.1 < $1.1}) {
    print("\(k):\(v)")
}

Swift 3, it also works:

for (k,v) in (Array(yourDictionary).sorted {$0.1 < $1.1}) {
    print("\(k):\(v)")
}