PyQt run time issue

Question

I want my code to run by showing the qtwidget and then running the forloop, but it runs the forloop then shows my widget to me. Why is this?

class tes(QWid         


        

Answer 1

Add QApplication.processEvents() before loop. Your widget will be shown, but unresponsive. To make application responsive, add processEvents() calls to some steps of your loop.

Example:

def __init__(self):
    super(tes, self).__init__()
    self.initUI()
    QApplication.processEvents()
    for i in range (1000000):
        if not i % 3:  # let application process events each 3 steps.
            QApplication.processEvents()
        print("s")