What is the point of `void func() throw(type)`?

Question

I know this is a valid c++ program. What is the point of the throw in the function declarement? AFAIK it does nothing and isnt used for anything.

#include &l         


        

Answer 1

This is a C++ exception specification. It declares that the particular function will potentially throw a std::exception type.

In general though exception specifications in C++ are considered a feature to avoid. It's an odd feature in that it's behavior is declared at compile time but only checked at runtime (very different from say Java's version).

Here is a good article which breaks down the feature

• http://www.gotw.ca/publications/mill22.htm