Find Mondays between 2 dates

Question

I need to display dates of all Mondays in the given date range.

For example, if my start date is 01/05/2015 and end date is 31/05/2015, I

Answer 1

Refer: Select dates of a day between two dates.

SELECT [Day],[Dt] FROM dbo.fnGetDatesforAday('7/1/2008','8/31/2008','Sunday')


CREATE FUNCTION fnGetDatesforAday
(
      -- Add the parameters for the function here
      @DtFrom DATETIME,
      @DtTo DATETIME,
      @DayName VARCHAR(12)
)

RETURNS @DateList TABLE ([Day] varchar(20),Dt datetime)

AS
BEGIN
      IF NOT (@DayName = 'Monday' OR @DayName = 'Sunday' OR @DayName = 'Tuesday' OR @DayName = 'Wednesday' OR @DayName = 'Thursday' OR @DayName = 'Friday' OR @DayName = 'Saturday')
      BEGIN
            --Error Insert the error message and return

            INSERT INTO @DateList
            SELECT 'Invalid Day',NULL AS DAT
            RETURN
      END 

      DECLARE @TotDays INT
      DECLARE @CNT INT

      SET @TotDays =  DATEDIFF(DD,@DTFROM,@DTTO)-- [NO OF DAYS between two dates]

      SET @CNT = 0
      WHILE @TotDays >= @CNT        -- repeat for all days 
      BEGIN
        -- Pick each single day and check for the day needed
            IF DATENAME(DW, (@DTTO - @CNT)) = @DAYNAME
            BEGIN
                  INSERT INTO @DateList
                 SELECT @DAYNAME,(@DTTO - @CNT) AS DAT
            END
            SET @CNT = @CNT + 1
      END
      RETURN
END