Converting colon separated list into a dict?

Question

I wrote something like this to convert comma separated list to a dict.

def list_to_dict( rlist ) :
    rdict = {}
    i = len (rlist)
    while i:
        i          


        

Answer 1

You mention both colons and commas so perhaps you have a string with key/values pairs separated by commas, and with the key and value in turn separated by colons, so:

def list_to_dict(rlist):
    return {k.strip():v.strip() for k,v in (pair.split(':') for pair in rlist.split(','))}

>>> list_to_dict('a:1,b:10,c:20')
{'a': '1', 'c': '20', 'b': '10'}
>>> list_to_dict('a:1, b:10, c:20')
{'a': '1', 'c': '20', 'b': '10'}
>>> list_to_dict('a   :    1       , b:    10, c:20')
{'a': '1', 'c': '20', 'b': '10'}

This uses a dictionary comprehension iterating over a generator expression to create a dictionary containing the key/value pairs extracted from the string. strip() is called on the keys and values so that whitespace will be handled.