Selection Sort in JavaScript

Question

function newsort(arr, left, right){    

for(var i= left; i < right; ++i){
    var min = i;
    for (var j = i; j < right; ++j){
        if (arr[min] > arr[         


        

Answer 1

Eloquent solution:

const selectionSort = (items) => {
  items.forEach((val, i, arr) => {
    const smallest = Math.min(...arr.slice(i))
    const smallestIdx = arr.indexOf(smallest)

    if (arr[i] > arr[smallestIdx]) {
      const temp = arr[i]
      arr[i] = arr[smallestIdx]
      arr[smallestIdx] = temp
    }
  })

  return items
}

Standard solution:

const selectionSort = (arr) => {
  for (let i=0; i <= arr.length-1; i++) {
    // find the idnex of the smallest element
    let smallestIdx = i

    for (let j=i; j <= arr.length-1; j++) {
      if (arr[j] < arr[smallestIdx]) { 
        smallestIdx = j
      }
    }

    // if current iteration element isn't smallest swap it
    if (arr[i] > arr[smallestIdx]) {
      let temp = arr[i]
      arr[i] = arr[smallestIdx]
      arr[smallestIdx] = temp
    }
  }

  return arr
}

Testing:

console.log( // [14, 29, 56, 72, 92, 98] 
  selectionSort([29, 72, 98, 14, 92, 56]) 
)