Subclass constructors - Why must the default constructor exist for subclass constructors?

Question

Given a random class:

public class A {
    public T t;

    public A () {}  // <-- why is this constructor necessary for B?
    public A (T t) {
         


        

Answer 1

If you don't make a call to a super constructor using super(i) as the first line of your constructor it will implicitly call the default super constructor