C++ equivalent of python: tf.Graph.get_tensor_by_name() in Tensorflow?

Question

What is the C++ equivalent of python: tf.Graph.get_tensor_by_name(name) in Tensorflow? Thanks!

Here is the code I am trying to run, but I get an empty output

Answer 1

there is a way to get neural node from graph_def directly. if u only want the shape\type of node: "some_name":

void readPB(GraphDef & graph_def)
{

    int i;
    for (i = 0; i < graph_def.node_size(); i++)
    {
        if (graph_def.node(i).name() == "inputx")
        {
            graph_def.node(i).PrintDebugString();
        }
    }
}

results:

name: "inputx"
op: "Placeholder"
attr {
  key: "dtype"
  value {
    type: DT_FLOAT
  }
}
attr {
  key: "shape"
  value {
    shape {
      dim {
        size: -1
      }
      dim {
        size: 5120
      }
    }
  }
}

try member functins of the node and get the informations.