How can I convert String to Double without losing precision in Java?

Question

Tried as below

String d=new String(\"12.00\");
Double dble =new Double(d.valueOf(d));
System.out.println(dble);

Output: 12.0

But i

Answer 1

Your problem is not a loss of precision, but the output format of your number and its number of decimals. You can use DecimalFormat to solve your problem.

DecimalFormat formatter = new DecimalFormat("#0.00");
String d = new String("12.00");
Double dble = new Double(d.valueOf(d));
System.out.println(formatter.format(dble));

I will also add that you can use DecimalFormatSymbols to choose which decimal separator to use. For example, a point :

DecimalFormatSymbols separator = new DecimalFormatSymbols();
separator.setDecimalSeparator('.');

Then, while declaring your DecimalFormat :

DecimalFormat formatter = new DecimalFormat("#0.00", separator);