C++ : &(std::cout) as template argument

Question

Why isn\'t it possible to pass std::cout\'s address as template argument? Or if it is possible then how?

Here is what I tried:

#include          


        

Answer 1

This fixes your code, omit the parenthesis:

#include 

template
class MyClass
{
public:
    void disp(void) { 
        (*stream) << "hello"; 
    }
};

int main(void)
{
    MyClass<&std::cout> MyObj;
    MyObj.disp();

    return 0;
}

Live Demo

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A more detailed explanation why can be found here:

Error with address of parenthesized member function