Currently Executing Procedure Name within the Package

Question

Is there a way to get the currently executing procedure name within the package?

create or replace package test_pkg
as
    procedure proc1;
end test_pkg;

cre         


        

Answer 1

An approach using the idea borrowed from here : http://www.orafaq.com/forum/t/173023/

Note : This works fine only in Oracle 12c. For 11g, It only gives Package name.

Create a procedure called show_caller. This uses the OWA_UTIL.WHO_CALLED_ME procedure.

create or replace procedure show_caller
as
   l_owner  varchar2(200);
   l_name   varchar2(200); 
   l_lineno number;
   l_caller varchar2(200);
begin 
   OWA_UTIL.WHO_CALLED_ME (l_owner, l_name,l_lineno,l_caller);
   dbms_output.put_line('Inside '||l_name);

end;
/

Now, you can write your package as:

CREATE OR replace PACKAGE test_pkg 
AS 
  PROCEDURE proc1; 
END test_pkg; 

/ 
CREATE OR replace PACKAGE BODY test_pkg 
AS 
  PROCEDURE Proc1 
  AS 
  BEGIN 
      show_caller;  -- proc1 calls show_caller 
  END proc1; 
END test_pkg; 

/ 

Execution.

SET SERVEROUTPUT ON
BEGIN
   Test_pkg.Proc1;
END;
/
Inside TEST_PKG.PROC1

Note that this will print the name of the procedure.If you want to use it as a variable, pass l_name(along with others if needed) as OUT variable from show_caller

Live SQL Demo ( Free OTN account required )

One other option is to use OWA_UTIL.GET_PROCEDURE function within the procedure: but it doesn't seem work for me in this context. I would be glad to know more about this from experts.