Problem with display multiple Toast in order one after another

Question

sorry for my bad English.
i want show two toast in order, in other word when first toast duration is over second toast appear.
this is my code :

Toas         


        

Answer 1

but only second toast message will appear. i think when show method of second toast will execute it will cancel previous toast (first toast)

When you call show method, it will put into message queue of UI thread, and the Toast will be shown in order. But you put two Toast at the same time, the latter will overlap the former.

i want show two toast in order, in other word when first toast duration is over second toast appear.

From Toast duration

private static final int LONG_DELAY = 3500; // 3.5 seconds 
private static final int SHORT_DELAY = 2000; // 2 seconds

To make the second toast display after duration of the first one, change your code to

Toast.makeText(this, "Toast1", Toast.LENGTH_SHORT).show();
Handler handler = new Handler();
handler.postDelayed(new Runnable()
{
    @Override
    public void run()
    {
        Toast.makeText(MainActivity.this, "Toast2", Toast.LENGTH_SHORT).show();
    }
}, 2000);

but is there any easier solution?

Using Handler is the easy and simple solution to achieve your task.