If I have a nested factor, in this case I have multiple \"Family\" levels that are contained in the factor \"Order\", I would like to potentially create a
Using facet_grid or facet_wrap will not build the graphic you are trying to build. You can, however, build a list of graphics and then plot them via gridExtra::grid.arrange. Here is an example
library(ggplot2)
library(gridExtra)
library(dplyr)
dat <-
structure(list(Species = c("Acanthocyclops robustus", "Acroperus harpae",
"Alona affinis", "Ascaphus truei", "Bosmina longirostris"), Intercept = c(-36.1182388331068,
-27.2140776216155, -25.7920464721491, -39.2233884219763, -31.4301301084581
), B = c(0.919397836908493, 0.716601987210452, 0.685455190113372,
1.04159758611351, 0.81077051300147), Bconf = c(0.407917065756464,
0.181611850119198, 0.254101713856315, 0.708582768458448, 0.234313394549538
), Order = c("Cyclopoida", "Diplostraca", "Diplostraca", "Anura",
"Diplostraca"), Family = c("Cyclopidae", "Chydoridae", "Chydoridae",
"Leiopelmatidae", "Bosminidae")), .Names = c("Species", "Intercept",
"B", "Bconf", "Order", "Family"), row.names = c(NA, 5L), class = "data.frame")
dat
# A ggplot object with NO data. Omit the order from the facet_grid call
g <-
ggplot() +
aes(Species, B) +
geom_point() +
facet_grid(. ~ Family,
scales = "free", space = "free") +
ylim(range(dat$B)) +
xlab("")
# Build a seperate graphic for each Order and title
plots <-
lapply(unique(dat$Order), function(o) {
g %+% dplyr::filter_(dat, ~ Order == o) + ggtitle(o)
})
# build as Grobs and plot via gridExtra::grid.arrange
plots %>%
lapply(ggplotGrob) %>%
arrangeGrob(grobs = .) %>%
grid.arrange(., ncol = 1)