Detect months with 31 days

Question

Is there an analogous form of the following code:

if(month == 4,6,9,11)
{
  do something;
}

Or must it be:

if(month == 4 ||         


        

Answer 1

If you're using C or Java, you can do this:

switch (month) {
  case 4:
  case 6:
  case 9:
  case 11:
    do something;
    break;
}

In some languages, you could even write case 4,6,9,11:. Other possibilities would be to create an array [4,6,9,11], some functional languages should allow something like if month in [4,6,9,11] do something;

As Lior said, it depends on the language.

EDIT: By the way, you could also do this (just for fun, bad code because not readable):

if ((abs(month-5) == 1) || (abs(month-10) == 1)) do_something;