Calculate leap year in Java [duplicate]

Answer 1

you could use a switch statment, with a few if statements inside the february case:

switch(month)
{
case 1:
    System.out.println("January " + year + " has 31 days");
    break;
case 2:
    int n=28;
    if(year%4==0 && (year%100!=0 || year%400==0)
        n++;
    System.out.println("February " + year + " has "+n+" days");
    break;
case 3:
    System.out.println("March " + year + " has 31 days");
    break;
case 4:
    System.out.println("April " + year + " has 30 days");
    break;
case 5:
    System.out.println("May " + year + " has 31 days");
    break;
case 6:
    System.out.println("June " + year + " has 30 days");
    break;
case 7:
    System.out.println("July " + year + " has 31 days");
    break;
case 8:
    System.out.println("August " + year + " has 31 days");
    break;
case 9:
    System.out.println("September " + year + " has 30 days");
    break;
case 10:
    System.out.println("October " + year + " has 30 days");
    break;
case 11:
    System.out.println("November " + year + " has 30 days");
    break;
case 12:
    System.out.println("December " + year + " has 31 days");
    break;
default case:
    System.out.println("Please enter the numerical value of the month you would like to view");
}

see http://download.oracle.com/javase/tutorial/java/nutsandbolts/switch.html for more info