Pass temporary object to function that takes pointer

Question

I tried following code :

#include 
#include
using namespace std;

string f1(string s)
{
   return s=\"f1 called\";
}

void f2(s         


        

Answer 1

Try this:

int main()
{
    string str;
    string str2 = f1(str); // copy the temporary
    f2(&str2);
}