Pass temporary object to function that takes pointer

Question

I tried following code :

#include 
#include
using namespace std;

string f1(string s)
{
   return s=\"f1 called\";
}

void f2(s         


        

Answer 1

Your program doesn't compile because f1 has a parameter and you're not passing any.

Additionally, the value returned from a function is an rvalue, you can't take its address.