By default when you use \"ActivateItem(new Control());\" your control is loaded into a ContentControl which with the name ActiveItem, fro example. . If I have multiple conte
If the ViewModel that gets binded to the UI contains a property with the name that matches a content control. The Content control view automatically gets resolved the the view supported by this property, provided this property itself is a ViewModel type and has been registed with Ioc container. For example
If there is a property LoginStatus on the main ViewModel (LoginStatus property itself is a ViewModel). The content control would correctly get rendered with the appropriate view.