Regex and escaped and unescaped delimiter

Question

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I have a string

a\\;b\\\\;c;d

which in Java looks like

String s = \"a\\\\;b\\\\\\\\;c;d\"         


        

Answer 1

This is the real answer i think. In my case i am trying to split using | and escape character is &.

    final String regx = "(?

In this code i am using Lookbehind to escape & character. note that the look behind must have maximum length.

(?

this means any | except those that are following ((?:[^&]|^)(&&){0,10000}&)) and this part means any odd number of &s. the part (?:[^&]|^) is important to make sure that you are counting all of the &s behind the | to the beginning or some other characters.