Pandas .loc without KeyError

Question

>>> pd.DataFrame([1], index=[\'1\']).loc[\'2\']  # KeyError
>>> pd.DataFrame([1], index=[\'1\']).loc[[\'2\']]  # KeyError
>>> pd.DataFrame         


        

Answer 1

This page https://pandas.pydata.org/pandas-docs/stable/indexing.html#deprecate-loc-reindex-listlike has the solution:

In [8]: pd.DataFrame([1], index=['1']).reindex(['2']) Out[8]: 0 2 NaN