Regex for managing escaped characters for items like string literals

Question

I would like to be able to match a string literal with the option of escaped quotations. For instance, I\'d like to be able to search \"this is a \'test with escaped\\\' val

Answer 1

>>> print re.findall(r"('([^'\\]|\\'|\\\\)*')",r""" Example: 'Foo \' Bar'  End. """)[0][0]

'Foo \' Bar'