I am looking for a fastest way to convert a byte array of arbitrary length to a hexadecimal string. This question has been fully answered here at StackOverflow for C#. Some
#include
#include
#include
#include
#include
#include
#include
int main()
{
std::vector v;
v.push_back( 1 );
v.push_back( 2 );
v.push_back( 3 );
v.push_back( 4 );
std::ostringstream ss;
ss << std::hex << std::uppercase << std::setfill( '0' );
std::for_each( v.cbegin(), v.cend(), [&]( int c ) { ss << std::setw( 2 ) << c; } );
std::string result = ss.str();
std::cout << result << std::endl;
return 0;
}
Or, if you've got a compiler that supports uniform initialization syntax and range based for loops you can save a few lines.
#include
#include
#include
#include
#include
int main()
{
std::vector v { 1, 2, 3, 4 };
std::ostringstream ss;
ss << std::hex << std::uppercase << std::setfill( '0' );
for( int c : v ) {
ss << std::setw( 2 ) << c;
}
std::string result = ss.str();
std::cout << result << std::endl;
}