NaN is removed when using na.rm=TRUE

Question

This reproducible example is a very simplified version of my code:

x <- c(NaN, 2, 3)

#This is fine, as expected
max(x)
> NaN

#Why does na.rm remove N         


        

Answer 1

It's a language decision:

> is.na(NaN)
[1] TRUE

is.nan differentiates:

> is.nan(NaN)
[1] TRUE
> is.nan(NA)
[1] FALSE

So you may need to call both.